Question

Abcd is a trapezium with ab=cd and ad//bc ad=10cm and bc=18cm.If area of abcd is 70 cm^2.Find value of cd?

Answer 1

We are given
ab = cd
ad ||bc
ad = 10cm
bc = 18cm

also given
area of Trapezium = 70cm^2

We have to find cd

Let cd be the height of Trapezium

Then,
We know that
area of Trapezium = 1 (sum of parallel side)h /2

70 = 1(10 + 18)h/2
70×2 = 1(10 + 18)h
140 = (10 + 18)h

140 / 10+18 = h
140 / 28 = h

5cm=h Answer