ABCD is a trapezium with AB parallel to DC. If AB = 10 cm, AD = BC = 4 cm and ang. DAB = ang. CBA = 60°, calculate (i) the length of CD, (ii) the distance between AB and CD.
Solve through similarity of triangles.
Answers
Answered by
8
Step-by-step explanation:
see the picture
If it is useful for you please like
Attachments:
Similar questions
Physics,
13 hours ago
Math,
1 day ago
Business Studies,
1 day ago
Math,
8 months ago
Math,
8 months ago