Question

Physics ; A child, jumping on a trampoline, reaches a height of 0.925 m. what was his speed when he left the trampoline?

Answer 1

A child throws the ball straight up. And if the ball is to reach a height of 9.8 m, we want to know the minimum initial velocity that must be imparted to the ball. So um we know that we're gonna be using the vehicles V not plus ap but in this case we see that the velocity of the ball is going to be a result of the not minus G. P. Because the gravity is pulling it down. We want at the highest point We wanted to reach a height of 9.8 so it's going to be zero. Um now we have two different variables Vienna and T. So let's consider um SFP which equals one half or negative one half G. T. Square plus Vienna T plus S not. Which is just going to be zero. We want to know how it will get to A height of 9.8 given this value. So we're going to solve this for tea and be able to input that in here. So that'll give us our final answer.

${vf}^{2} = {vi}^{2} + 2 \times a \times d \\ vf = 0 \\ a = - 9.8 \\ 0 = {vi }^{2} + 2 \times - 9.8 \times 0.925 \\ vi = \sqrt{18.3 } \\ = 4.26m/s$

The answer is 4.26m/s