Question

Abcd is a trapezium with ad and bc parallel sides. F is a point on bc. The ratio of the area of abcd to that of afd is

Answer 1

Answer:

(AD + BC ) : AD

Step-by-step explanation:

Let h = height of trapezium and AD = a, BC = b

Area of ABCD = $\frac{1}{2}$ × h × (a + b)

Area of ΔAFD = $\frac{1}{2}$ × a × h

Ratio of area of ABCD : AFD = (a+b) : a

                                              = (AD + BC ) : AD