Question

ABCD is a trapezium with height 18 cm .a perpendicular from A to longer side CD meet at point F . Angle ACF =x, CF=7cm, AB=9cm . Find x and the area of trapezium.

Answer 1

Answer:

hey dear...

given ,

height =18cm

Angle A CF=x

CF =7cm

AB=9cm

Area of a trapezium ABCD

= area (∆DFA) + area (rectangle DFEC) + area (∆CEB)

= (¹/₂ × AF × DF) + (FE × DF) + (¹/₂ × EB × CE)

= (¹/₂ × AF × h) + (FE × h) + (¹/₂ × EB × h)

= ¹/₂ × h × (AF + 2FE + EB)

= ¹/₂ × h × (AF + FE + EB + FE)

= ¹/₂ × h × (AB + FE)

= ¹/₂ × h × (AB + DC) square units.

= ¹/₂ × (sum of parallel sides) × (distance between them) .

hope it's helpful for you..