ABCD is an isosceles trapezium. AB and DC are the parallel sides. Perpendiculars AG and BH are drawn on CD. Prove that ∆ADG congurent to ∆BHC.
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Answer:
by rhs congurency
Step-by-step explanation:
ag and bh are prependiculars to dc
angle agd =90 =angle bhc..eq1
it is isoceles trap so ad = bc ...eq2
and ag = bh ...eq3 as length of prependiculars are equal
from 1 2 3 triangles are congurent by rhs
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