Question

♡ ABCD is an isosceles trapezium with AB ||DC Prove that AC=BD

Answer 1

Answer:

ΔDAC and ΔDBC lie on the same base DC and

between the same parallels AB and CD.

Ar(ΔDAC) = ar(ΔDBC)

=> ar(ΔDAC) – ar(ΔDOC) = ar(ΔDBC) – ar(ΔDOC)

=> ar(ΔAOD) = ar(ΔBOC)

Hence Proved