Question

abcd is cyclic quadrilateral of ∠bcd=100° and ∠abd=70° then find ∠adb

Answer 1

ABCD is a cyclic quadrilateral

∠ADB = 30°

∠DCA = 80°

∠ADB = ∠ACB = 30° (Angle on the same segment)

Now,

∠BCD = ∠ACB + ∠DCA

= 30° + 80°

= 110°

∠OAB + ∠BCD = 180°

∠OAB + 110° = 180°

∠OAB = 70°

Answer 2

Answer:

Step-by-step explanation:

∠abd=70°

So ∠abc=2*70

=140°

∠Abc +∠adc=180

∠adc=40

So ∠adb=20°

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