Question

Abcd is parallelogram . O is any point on AC . PQ || AB and LOM || AD . prove that ar (llgm DLOP) = ar ( || gm BMOQ)

Answer 1

FIGURE IS IN THE ATTACHMENT

Since,a diagonal of a parallelogram divides it into two Triangles of equal area.
Since, AO & OC are diagonals of a parallelogram AMOP & OQCL
ar(∆APO) = ar(∆AMO) ………..(1)
ar(∆OLC) = ar(∆OQC) ………..(2)
ar(∆ADC) = ar(∆ABC)
ar(∆APO) + ar(||gmDLOP) +ar(∆OLC) =
ar(∆AMO) + ar(||gm BMOP) +ar(∆OQC) …(3)
Subtract eq 1 & 2 from 3
ar(||gmDLOP) = ar(||gm BMOQ)

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