ABCD is quadrilateral E,F,G and H are the midpoints of AB,BC,CDandDA respectively .prove that EFGH is a rhombus
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ar(quadrilateral ABCD ) = ar ( Rhombus EFGH )
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GIVEN, quad ABCD
E,F,G,H are mid points
To Prove, EFGH is a parallelogram.
Proof,
Join AC and BD,
In ∆ADC
H is mid point of AD and G is mid point of DC.
So by mid point theorem,
HG || AC and HG= AC/2.......(1)
Similarly,
EF ||AC and EF =AC/2........(2)
By (1) & (2),
HG || EF and HG=AF
We know,
If in a quad opposite sides are equal and parallel then it is a parallelogram.
Hence proved
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Anonymous:
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