Abcd is quadrilateral in which ab=bc,and ad=cd.show bd bisects both angles of absc and adc
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we can do this simply by congurency of triangle ABD and triangle DBC.
ad=dc , given
ab=bc, given
bd=bd ,common
hence by sss congurency triangles are congurency and by cpct Angle ADB Nd angle BDC are equal so bd bisects angle d
same for other one
ad=dc , given
ab=bc, given
bd=bd ,common
hence by sss congurency triangles are congurency and by cpct Angle ADB Nd angle BDC are equal so bd bisects angle d
same for other one
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