ABCD is quadrilateral in which AB = BC and AD = CD. Show that BD bisects both the angles ABC and ADC
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In triangle ABD& CBD
AB=BC(given)
AD=CD(given)
BD=BD(Common)
so triangle ABD congruent triangle CBD (SSS)
so, angle ABD=angle DBC(CPCT)
angle ADB=angle BDC (CPCT)
AB=BC(given)
AD=CD(given)
BD=BD(Common)
so triangle ABD congruent triangle CBD (SSS)
so, angle ABD=angle DBC(CPCT)
angle ADB=angle BDC (CPCT)
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22
please mark it brainliest.
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