Math, asked by kailashbenpstel, 2 months ago

ABCD is quadrilateral in which AB is parallel to CD and AD =BC =5cm. if angle A =105, find the value of angle of B​

Answers

Answered by nikhilsingh2614
2

Answer:

75°

Step-by-step explanation:

Since adjacent angle of parallelogram are supplement

so. angle A + angle B = 180°

Angle B = 180° - angle A

= 180° - 105°

= 75 °

Hope you get it ☺️

Answered by abusince05
0

Answer:

Given:ABCD is a quadrilateral in which AB parallel to CD and AD=BC=5 if ∠A=105º

We need to find the value of ∠B

Solution:

From the properties of a parallelogram, we know that

Vertically opposite angles are equal.

Hence ∠A and ∠B forms Co interior angles and the sum of Co interior angles is 180º

∠A + ∠B= 180º

105 +∠B =180º

∠B=180º-105º

∠B=75º

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