Question

ABCD is quadrilateral. Is AB+BC+CD+DA <2 (AC+BD)

Answer 1

ABCD is a quadrilateral then prove thatAB + BC + CD + DA < 2(AC + BD)?ABCD is a quadrilateral and AC, andBD are the diagonals. Sum of the two sides of a triangle is greater than the third side. Joining A to C and B to D, we get traiangles, ABC, BDC, ACD and ABD.

Answer 2

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