Question

ABCD is rectangle. On side DC a semicircle is drawn.
From the information given in the figure, find out area of
shaded portion. ​

Answer 1

Answer:

area of ABC rect =l*b

11*7

77

area of semi circle = πr^2

22/7*3.5*3.5/2

22*0.5*3.5/2

38.5/2

19.25

area of unshaded rect = l *b

7*5

35

area of shaded portion =77-

(19.25+35)

=22.75

hope it might be right

Answer 2

Answer:

area of shaded portion = 36.5 cm^2

ar of semicircle = pi*r^2/2

ar of rectangle = l*w

Step-by-step explanation:

r=3.5

ar of semicircle =( 22/7 * 3.5)/2

= 5.5

ar of rectangle = 5 * 7

= 35

ar of full rectangle = 11*7

=77

ar of shaded portion = (ar of semicircle + ar of rectangle ) - ar of the full rectangle

= (5.5+35) - 77

area of shaded portion = 36.5 cm^2