ABCD is square and traingle DCE is an equilateral traingle inscribed in it .if EF is drawn perpendicular to BC ,find the measure of angle BEF?
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Answer:
60°
Step-by-step explanation:
As tri. DEC is equilateral ....
so angle ECD = 60° (angles of equi. triangle)
angle ECF = angle BCD - angle ECD
angle ECF = 90-60 all side angles of square are 90°)
/_ ECF =30
angle CEF = 180 - ( 90 +30) .......(angle sum prop of triangle)
ANGLE CEF= 60
As line DEB is straight line (180°)
angle DEC + angle CEF +angle BEF = 180°( linear pair)
60 + 60 + angle BEF = 180
angle BEF= 180 - 120
angle BEF = 60
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