ABCD is straight line where AB= 2cm and AD=40 cm, AC:CD= 7:3, Find BC
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AB+BC+CD=AD=40cm
Before that
AC/CD=3/7
(AB + BC)/CD=3/7
7 (AB + BC)= 3 CD
7 (2+BC)=3CD
CD=(14+7BC)/3
Now,
2+BC+(14+7BC)/3=40
(3BC+14+7BC)/3=38
PlZ
Edit---wrong answer
Before that
AC/CD=3/7
(AB + BC)/CD=3/7
7 (AB + BC)= 3 CD
7 (2+BC)=3CD
CD=(14+7BC)/3
Now,
2+BC+(14+7BC)/3=40
(3BC+14+7BC)/3=38
PlZ
Edit---wrong answer
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