Question

ABCD is trapezium with AB parallel to DC then the triangle similar to∆AOB is

Answer 1

Answer:

Triangle COD is the correct answer

Answer 2

Solution :-

Given that, ABCD is trapezium with AB parallel to DC .

so, In ∆AOB and ∆COD we have,

→ ∠AOB = ∠COD { Vertically opposite angles. }

→ ∠OAB = ∠OCD { since AB || DC , alternate angles. }

then,

→ ∆AOB ~ ∆COD { By AA similarity .}

hence, ∆AOB is similar to ∆COD .

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