Math, asked by nishthajain15, 3 months ago

ABCD se kite if angle BCD equals to 40 degree find angle bdc and angle abc​

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Answered by Sanju1534
11

Answer:

since triangle BCD is an isosceles triangle

therefore, angle BDC = angle CBD = x

angel BCD = 40

So,

x+x+40 = 180

=> 2x = 180-40

=> 2x = 140

=> x = 140/2

=> x = 70

angle BDC = angle CBD = 70 degree

Triangle BAD is an equilateral triangle

therefore, all angles are equal in triangle BAD

Let, all the angles of triangle BAD = x

So,

x+x+x = 180

=> 3x = 180

=> x = 180/3

=> x = 60

angle ABD = 60 degree

therefore, angle ABC = 70 + 60 = 130 degree.

ans. angle BDC = 70 degree, angle ABC = 130 degree.

Answered by DishitaChoudhury
0

You can find the answer in this attachment. hope it helps.

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