Question

Abcd us a parallelogram and e is the mid point of bc show by vector method that ae and bd trisect each other

Answer 1

ABCD is a parallelogram. E is the midpoint of BC. DE and AB produced meet at F. How to prove that AF=2AB.

Triangles ADF and CEF are similar as BE is parallel to AD. Since BE is half of BC and so also of AD, EF will be half of DF and BF will be half of AF. Since BF =AF/2, AF = 2AB. Proved.

Answer 2

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