Question

Ab is a chord of a circle of radius 14cm. The chord subtends a right angle at the centre of the circle. Find the area of the minor segment

Answer 1

Answer:

Step-by-step explanation:

Given radius (r) = 14cm = OA = OB θ = angle at centre = 60° In ΔAOB, ∠A = ∠B [angles opposite to equal sides OA and OB] = x By angle sum property ∠A + ∠B + ∠O = 180° x + x + 60° = 180° ⇒ 2x = 120° ⇒ x = 60° All angles are 60°, OAB is equilateral OA = OB = AB Area of minor segment = area of sector – area of ΔOAB