Question

Abc is a right triangle right-angled at c and ac= √3 bc. Prove that abc=60o

Answer 1

Draw a median CD to AB from C.

Now, by Pythagoras theorem in ABC, AB=2*BC.

Thus, BD= half of AB = BC.

But, the point of bisection of the hypotenuse is equidistant from all sides.

Thus, CD=BD=AD.

That implifies, CD=BD=BC.

Thus, CDB is an equilateral triangle.

Therefore, angle DBC = angle ABC = 60 degrees.

Answer 2

Answer:here you go

Step-by-step explanation: