Question

ABDF is a square and BC = EF in the given figure. Prove that (i) ABC ≅ AFE (ii) ACG ≅ AEG​

Answer 1

Step-by-step explanation:

Given,

BC=EF

Since ABCD is a square, sides are equal

AF=AB

∠B=∠F

Therefore from SAS theorem

ABC≅AFE

⟹AC=AE Hence the triangle is isoceles.

AEG≅ACG

Therefore from ASA theorem

ACG≅AEG

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Answer 2

Step-by-step explanation:

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