Question

Abdi has two electric train sets: A and B. Each train is on its own circular track. He start both trains at the same time. Train A return to its starting point every 12 seconds. Train B return to its starting point every 9 seconds. If the train continue traveling what is the least amount of time, in seconds, that both the train will arrive at the starting points at the same time?​

Answer 1

Abdi has two electric train sets: A and B.

Each train is on its own circular track.

He start both trains at the same time.

Train A return to its starting point every 12 seconds.

Train B return to its starting point every 9 seconds.

If the train continue traveling . To find the least amount of time, in seconds, we have to

$Find \: the \: LCM \: of \: 12 \:and \: 9, \\we \:get$

$LCM (12,9) = 36$

Therefore.,

$\blue {Both \:the\: trains\:will \:arrive\: at \:}\\\blue {the \:starting \:points\: at }\green { =36 \:seconds }$

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Answer 2

Answer:

36

Step-by-step explanation:

A, returns to the starting point every 12 seconds, while B returns every 9 seconds.

Find the LCF of them both.
12 x 3 = 36
9 x 4 = 36. (They're both the same)

Therefore, they will both arrive at the starting point every 36 seconds