Math, asked by kogbua20, 3 months ago

Abe, Bella, Cai, Dante, and Ellis each bring a present to a gift exchange. They each leave with someone else's gift. Abe left with Cai's gift and Dante left with Bella's. How many ways could the remaining gifts be distributed?

Answers

Answered by amitnrw
2

Given : Abe, Bella, Cai, Dante, and Ellis each bring a present to a gift exchange.

They each leave with someone else's gift.

Abe left with Cai's gift

Dante left with Bella's

To Find : How many ways could the remaining gifts be distributed?

Solution:

A left with C's Gift

D left with  B's Gift

Person left         Gift Left

B                       A

C                       D  

E                       E

each leave with someone else's gift. and E can not get gift of E

hence E can get gift in 2 Ways

then B or C can get gift in 2 ways

and last one in 1 way

Hence 2 * 2 = 4 Ways

other way

3 person 3 gift = 3! = 6 ways

when E gets E  then 2! = 2 Ways   ( this case is not possible(

Hence 6 - 2= 4

remaining gifts can be distributed in 4 Ways

B  - D  ,   C -E ,           E - A

B  - E  ,   C -D ,           E - A

B  - A  ,   C -E ,           E - D

B  - E  ,   C -A ,           E - D

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