Abhay jogs from one end A to the other end B of a straight 300m road in 2 minutes 30 seconds and then turns around and jogs 100m back to point C in another minute. What is the average velocity and speed in jogging from A to B and from A to C?
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Answered by
41
hey friend!!!!!!
Velocity = dispacement / time
Speed = distance / time
a) when he jogs from A to B on a straight road,
=> displacement = distance = 300m
=> time = 2 minutes 30 seconds = 150 s
=> velocity = 300/150 = 2 m/s
=> speed = 300/150 = 2m/s
b)when he jogs from A to B and turns back to C,
=> displacement = 300-100 = 200m
=> distance = 300+100 = 400m
=> time = 3 minute 30 second = 210 s
=> velocity = 200/210 = 20/21 m/s
=> speed = 400/210 = 40/21 m/s
hope it will help you
Velocity = dispacement / time
Speed = distance / time
a) when he jogs from A to B on a straight road,
=> displacement = distance = 300m
=> time = 2 minutes 30 seconds = 150 s
=> velocity = 300/150 = 2 m/s
=> speed = 300/150 = 2m/s
b)when he jogs from A to B and turns back to C,
=> displacement = 300-100 = 200m
=> distance = 300+100 = 400m
=> time = 3 minute 30 second = 210 s
=> velocity = 200/210 = 20/21 m/s
=> speed = 400/210 = 40/21 m/s
hope it will help you
Vaishnavi9118:
why distance 200
sorry
why distance from a to c 300+100 = 400
because he has turned to c
distance to 400 hi hogi na
displacement 200 hoga
smj ni aaya
aa gaya
thnx
Answered by
3
Answer:
Thanks for the points
Explanation:
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