Math, asked by umangdubey0242, 7 months ago

Abhimanyu has three times as many Rupees to coins as he has rupees 5 coins if the total money he has is rupees 77 how many coins of each denomination does he have​

Answers

Answered by KamaldevSharma
13

Answer:

₹5 coins =7

₹2 coins =21

Step-by-step explanation:

let the no. of ₹5 coins be x,

=>no. of ₹5 coins=x,

no. of ₹2 coins=3x

A. T. Q,

(₹5×x)+(₹2×3x)=77

5x+6x=77

=>11x=77

=>x=77/11=7

₹5 coins=7

₹2 coins=3×7=21

PLEASE MARK AS BRAINLIEST......

Answered by mohishkhan9996
7

Answer:

kon ho ap orr kya chahiye bol kaha rehta hai tu......bol tuhje. to me btaunnga

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