Question

Abhimanyu invested Rs 100000 at 13 % per annum compounded annually. Find the following: (i) The amount standing to his credit at the end of the second year. (ii) The interest for the third year.

Answer 1

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Step by Step Explanation ;-
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Given ;
• Amount = ₹1,00,000
• Rate = 13% p.a.
• Time = 3 years ( according to understanding )

__________________________

Now , Asked is ;

(i) The amount standing to his credit at the end of the second year.
(ii) The interest for the third year.

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(i) First Question ;

• We know the Formula ;-

=> A = P ( 1+R x 1/2 ÷ 100 )2n

=> A = 100000 ( 1 + 13 x 1/2 ÷ 100 )4

=> A = 100000 ( 1 + 6.5/100)4

=> A = 100000 ( 106.5/100)4

=> A = 100000 x 106.5/100 x 106.5/100 x 106.5/100 x 106.5/100

=> A = ₹ 128,646.63

• Hence , the amount standing to his credit at the end of the second year is ₹ 128,646.63.

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(ii) Second Question ;-

• According to the formula above discussed ;-

=> A = P ( 1+R x 1/2 ÷ 100 )2n

=> A = 128,646.63 ( 1 + 6.5 /100 )2

=> A = 128,646.63 x 106.5/100 x 106.5/100

=> A = ₹ 145,914.23

• We know that ;

=> CI = A - P

=> CI = 145,914.23 - 100000

=> CI = ₹ 45,914.23

Hence ,

The CI = ₹ 45,914.23 and as above taken interest for the third year is 128,646.63.

_____________________

- Regards
@dmohit432

Answer 2

Answer:

rupee 127690

rupess16599.70

Step-by-step explanation:

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