Abhinav gets 60 marks and failed by 20 marks in chemistry paper. If maximum mark is 200 find the pass percent
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Given, Maximum marks = 200.
Marks he got = 60.
Marks he get failed by = 20.
Total pass marks = 60 + 20
= 80.
Pass % = (pass marks)/Total * 100
⇒ (80/200) * 100
⇒ 40%.
Therefore, Pass percent = 40%.
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siddhartharao77:
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Answered by
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given , abhinav got = 60 marks
and, as failed by =20 marks
maximum mark = 200
so, pass mark = 60+20=80
now pass percent= 80×100/200= 40℅
so tha pass percent= 40℅
hope it help you
and, as failed by =20 marks
maximum mark = 200
so, pass mark = 60+20=80
now pass percent= 80×100/200= 40℅
so tha pass percent= 40℅
hope it help you
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