Math, asked by tanishsingh5890, 1 year ago

Abhinav purchase a track suit for rs 2400 cash or for rs 1000 cash down payments and two equal monthly installments of Rs 800 each.Find the rate percentage.

Answers

Answered by vikashjaiswal5935
9

Solution:

Let the interest of rate be R% , then

Amount(as Principal) for next 2 months will be = Rs 2400- Rs 1000 = Rs 1400.

As we know that S.I = P×R×T/100

Now at rate of R% , the amount will be ( after 2 Months )  = 1400+1400×R×2/100×12 ----(1)

According to the Question

Total amount for the 2 installment will be =800(800+800×R×1/1200)  ---(2)

Now solving equation 1 and 2 we get.

1400+2800R/1200 = 1600+800R/1200

∴R = 120%

Hence Rate of interest = 120%

Answered by amitnrw
0

Answer:

Simple interest

r = 85.7% per annum

7.15 % per month

Compound Interest

r = 9.38 % per month

r = 112.6 % per annum

Step-by-step explanation:

Abhinav purchase a track suit for rs 2400 cash or for rs 1000 cash down payments and two equal monthly installments of Rs 800 each.Find the rate percentage.

Cost Price at down payment = Rs 2400

if he made Rs 1000 down payment then remaining payment = 2400 - 1000

= Rs 1400

He will make payment of Rs 800 + 800 = Rs 1600 more

Interest paid = Rs 1600 - Rs 1400 = Rs 200

Interest is paid on Amount Rs 1400

Rs 200 interest paid on Rs 1400 in two months

Simple interest Rate = r % per annum

200 = 1400 * r * (2/12)/100

=> r = 600/7

=> r = 85.7% per annum

7.15 % per month

if Compound interest r % per month

Then interest for 1st month

= 1400 * r * 1/100 =

= 14r

in 1st installment  Principle paid = 800 - 14r   & interest paid = 14r

remaining principle = 1400 - (800 - 14r) = 600 + 14r

Interest paid in second installment = (600 +14r) ) * r * 1/100

= 6r + 0.14r²

total interest paid in 2 months = Rs 200

14r + 6r + 0.14r² = 200

0.14r² + 20r - 200 = 0

7r² + 1000r - 10000 = 0

r = (- 1000 + √(1000000 + 280000) )/14

r = 9.38 % per month

r = 112.6 % per annum

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