Math, asked by debalinadass2448, 1 year ago

abhishek takes 6 days less than the time taken by anubhav to finish a piece of work if both of them together finish the work in 4 days find the time taken by anubhav alone to finish the work

Answers

Answered by desiboyz3
0
24 days will be the answer
Attachments:
Answered by prajwal096
0

Answer:

12 days

Step-by-step explanation:

Step -1: Finding the work done by A and B in a day.

                Let B takes a total of x days to complete the work alone.

                So as know that A takes 6 days less than B we can write that A takes

                 x - 6 days to complete the work alone.

                Work done by B in a day =  

x

1

                Work done by A in a day =  

x−6

1

Step -2: Finding x .

                As we know that A and B together complete the work in 4 days,we can write

                 

x

1

+

x−6

1

=

4

1

                Taking LCM and solving we get,

                 

x(x−6)

x−6+x

=

4

1

                 

x(x−6)

2x−6

=

4

1

                Cross - multiplying we get,

                8x−24=x

2

−6x

                x

2

−14x+24=0

                x

2

−12x−2x+24=0

                x(x−12)−2(x−12)=0

                x=2,12

                We will reject x=2 as x - 6 will become negative.

Hence, B takes 12 days to complete the work alone.

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