A galvanometer having a coil resistance of 100ω gives a full scale deflection, when a current of 1ma is passed through it. the value of the resistance, which can convert this galvanometer into ammeter giving a full scale deflection for a potential difference of 10 v
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emf=V-Ir
emf=10-1×10^(-3)×100
E=10-0.1
E=99.9 V
Current=99.9/100
i=.999 amp
emf=10-1×10^(-3)×100
E=10-0.1
E=99.9 V
Current=99.9/100
i=.999 amp
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