Question

the value of 3x2 (x2-2x+1) for x=1 is​

Answer 1

Answer:

$3 \times 2(x2 - 2x + 1) \\ = 6(2 - 2 + 1) \\ = 6(1) \\ = 6$

Answer 2

Question

The value of

${3x}^{2} ( {x}^{2} - 2x + 1) if \: \bold{x = 1}$

Answer

What is given ?

• it is given here that 3x^2(x2-2x+1)
• if x=1

Solution

$\bold{ {3x}^{2}( {x}^{2} - 2x + 1)}$

$= > 3( {1}^{2} )( {1}^{2} - 2(1) + 1)$

$= > 3 \times 1(1 - 2 + 1)$

$= > </u><u>3</u><u>(1 - 3)$

$= > 3( - 2)$

$= > 3 \times ( - 2)$

$= > \bold{ - 6}$

Hence , the required answer is -6 .