Abicycle chain of length 1.6 m and of mass 1 kg is lying on a horizontal floor. if g=10ms−2, the work done in lifting it with one end touching the floor and the other end 1.6 m above the floor is
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mass of bicycle m = 1Kg
length h = 1.6 m
g = 10 m/s^2
Whenever the object like(ladder, stick, chain etc) are in contact with some other object or walls at the end points. its mass is divided into two equal parts.
work done W = mgh/2
therefore,
W = (1)(10)(1.6) / 2 = 8 J
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Answer:
m =1kg
h= 1.6m
g=10m/s^2
W=mgh/2
= 1×10×1.6/2
= 16/2
W=8J.
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