Abody is projected at a angle such that its
horizontal range is 3times the max. height det
ermine the angle of Projection
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1
Answer:
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Explanation:
given
horizontal range=u
²
sin
g
2Ф
maximum height=u
²
sin
2
2g
Ф
horizontal range = 3× maximum height
u
2
sin
g
2Ф
=3×u
2
sin
2
2g
Ф
sin2Ф=2sinФ.cosФ
2sinФ.cosФ=
2
3
.sin
2
Ф
tanФ=
3
4
Ф=tan⁻¹(
3
4
)
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