Question

Abody of mass 5 kg starts from rest and falls freely .the distance covered in one second is

Answer 1

Answer:

4.9 m

Explanation:

Distance covered in one second:

s = ut + at^2/2

During free fall (object dropped), u = 0, a = g

s = 0(1) + g(1)^2/2

s = 9.8/2

s = 4.9 m

To note: The distance covered is independent of the mass of the body since the acceleration due to gravity is same for object of any mass.

In the above problem, +y axis is taken vertically downwards. So don't confuse it with the + sign of g.