Abody of mass m falls freely through a height h. Its velocity when it just reaches the ground is -
(a) gh (b) (gh)12 (c) (2gh)12 (d) hg
please explian
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I think option d is correct...
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A body which is not moving at a height h at some point in time will have a maximum potential energy of mgh.
When the body starts falling down under influence of gravity, it will start building up it's kinetic energy which will be maximum when it just reaches the ground which will be 1/2mv². Now by law of conservation of energy the potential and kinetic energy equal each other. So by equating the two equations you will get v=2(gh)^1/2
When the body starts falling down under influence of gravity, it will start building up it's kinetic energy which will be maximum when it just reaches the ground which will be 1/2mv². Now by law of conservation of energy the potential and kinetic energy equal each other. So by equating the two equations you will get v=2(gh)^1/2
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