Question

About thrown vertically upwards with a velocity (v)rises to a certain height and then falls back to the ground
with the same final velocity (v). As its mass 'm' is a constant for a certain case, the value of p (mv) is the same
while being thrown, as also while it returns to the thrower Still the body's movement for the entire period of time
it is airborne, does not obey the law of conservation of momentum. Can you explain why?​

Answer 1

Answer:

For the first half, when ball A goes up V  

V  A  =U  A −gT

V  B=−gT

V  AB =V A  −V  B

V  AB  =U.......(1)

​ For the second half, when ball A comes down

V  A  =−gT

V  B =0

V  AB  =V  A −V  B

V  AB  =−gT........(2)

​  Hence from the equation (1) we observe that relative velocity is independent of T. Which will be valid till ball A reaches maximum height point. It is given time taken in reaching h is t.

Hence for the time t, V  

AB

​  

 will be constant, whereas after time t, relative velocity changes its direction and increases afterwards.

hope this answer helps you

Explanation:

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