Question

about what temperature the process will be spontaneous if ∆H = 20kj/mol and ∆s = 20J/k-1 mol-1​

Answer 1

Answer:

δG = δH - T × δS

For process to be spontaneous G should be less than zero that is

0 = δH - T δ S

δ H = T δ S

T = δ H / δ S

T = 20 × 1000 / 20

T = 1000 k