Question

above question is tough

Answer 1

Hello friend

Here, Initial kinetic energy is 25 J

v= 5 m/s

m=?

$\frac{1}{2} m {v}^{2} = 25 \\ \frac{1}{2} .m .{5}^{2} = 25 \\ m = 2 \: kg$

From here, we get m= 2 kg

When the velocity is doubled i.e.

v=5×2= 10 m/s

m=2 kg

$\frac{1}{2} .2. {10}^{2} = 100 \:$

Here, the Kinetic energy is 100 J

where v= 10 m/s and m= 2 kg

When velocity is increased by 3 ×

v= 5×3 = 15 m/s

$\frac{1}{2} .2. {15}^{2} = 225$

Here, the kinetic energy is 225 J

Where v= 5 m/s and m= 15 m/s

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Answer 2

Answer:

But aap ke is sawal ka karna kya hai