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given: ABCDE is a pentagon and its perimeter = 21cm
BE||CD and BC||DE AND BC is perpendicular to CD.
sol. therefore, if BE||CD and BC||DE AND BC is perpendicular to CD then BCDE is a rectangle.
now, BE=CD ......(opp. sides of rectangle)
therefore, x+y=5cm. .......(1)
now,
perimeter of ABCDE is 21 cm.
hence,
AB + BC + CD+ DE + EA= 21cm.
3 + (x-y) + (x+y) + (x-y) + 3 = 21
6 + 3(x-y) = 21
3(x-y) = 15
x - y = 5 ...........(2)
After solving (1) and (2), you will get
(adding 1 and 2 will cancel out y and you will get value for x then substitute it to get y)
x=5 and y=0
BE||CD and BC||DE AND BC is perpendicular to CD.
sol. therefore, if BE||CD and BC||DE AND BC is perpendicular to CD then BCDE is a rectangle.
now, BE=CD ......(opp. sides of rectangle)
therefore, x+y=5cm. .......(1)
now,
perimeter of ABCDE is 21 cm.
hence,
AB + BC + CD+ DE + EA= 21cm.
3 + (x-y) + (x+y) + (x-y) + 3 = 21
6 + 3(x-y) = 21
3(x-y) = 15
x - y = 5 ...........(2)
After solving (1) and (2), you will get
(adding 1 and 2 will cancel out y and you will get value for x then substitute it to get y)
x=5 and y=0
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