Question

abx square + (B square- AC) x- BC = 0 factorization

Answer 1

Given, abx^2 + (b^2 - ac) x - bc = 0

           abx^2 + b^2x - acx - bc = 0

          bx(ax + b) -c(ax+b) = 0

          (ax+b)(bx-c) = 0

           x = -b/a (or) x = c/b.


Hope this helps!