Question

AC = 24cm, BC=10cm, and O is the center of the circle . find the area of the shaded region. (π = 3.14 )

Answer 1

Hope it helps you

Please mark me as the brainliest

Answer 2

Solution :-

Finding the diameter of the circle at first:

AC=24cm, BC= 10 cm

So, AB= √AC²+BC² = √576+100 = √676 = 26cm

Therefore, the diameter of the circle is 26cm.

So,the radius is 13cm(r).

Now,finding the area of the semi-circle AOBC:

Area of semi-circle, A=(πr^2)/2 = 265.33 cm²

Now,finding the area of the right-angled triangle,ABC:

Area= ½ × base × height = 120cm²

Therefore, area of the shaded portion= Area of semi-circle AOBC - Area of triangle ABC= 265.33-120cm²= 145.33cm²

145.33 cm²

==============

@GauravSaxena01