Question

ac=48, cb=50, ab=?, bd=75,de=45 , be=?​

Answer 1

Step-by-step explanation:

Correct option is

B

50

0

Given: AD=BD=AC ∠CAE=75

∘

In △ABD

AD=BD

∠ABD=∠BAD=x (Isosceles triangle property)

∠ADC=∠ABD+∠BAD=2x (Exterior angle property)

In △ACD

AD=AC

hence, ∠ADC=∠ACD=2x (Isosceles triangle property)

Now, ∠CAE+∠BAC=180 (Linear pair)

75+∠BAC=180

∠BAC=105

∘

Sum of angles of triangle ABC = 180

∠BAC+∠ABC+∠ACB=180

105+x+2x=180

3x=75

x=25

Thus, ∠ACB=∠ACD=2x=2×25=50

∘

Answer 2

Answer:

Given: AD=BD=AC ∠CAE=75

∘

In △ABD

AD=BD

∠ABD=∠BAD=x (Isosceles triangle property)

∠ADC=∠ABD+∠BAD=2x (Exterior angle property)

In △ACD

AD=AC

hence, ∠ADC=∠ACD=2x (Isosceles triangle property)

Now, ∠CAE+∠BAC=180 (Linear pair)

75+∠BAC=180

∠BAC=105

∘

Sum of angles of triangle ABC = 180

∠BAC+∠ABC+∠ACB=180

105+x+2x=180

3x=75

x=25

Thus, ∠ACB=∠ACD=2x=2×25=50

∘