AC = 6 cm, ∠A = 60“ and ∠C = 45°. Measure AB and BC.
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First find angle B
B =180 - ( 60+45)= 75°
now use the sine rule ( law of sines)
BC / sin 60°=6/sin 75°
BC*(1+√3) (2√2) =6*√3/2
BC =(3√3) (1+√3)(2√2)
BC =(6√6)/(1+√3)*(1-√3)/(1-√3)
BC=(6√6-6√18)/(1-3)
BC =(6√6 -18√2) /-2
BC=( 9√2-3√6cm
And for AB
AB / sin 45°=6/sin 75°
AB=6√3-1) cm
B =180 - ( 60+45)= 75°
now use the sine rule ( law of sines)
BC / sin 60°=6/sin 75°
BC*(1+√3) (2√2) =6*√3/2
BC =(3√3) (1+√3)(2√2)
BC =(6√6)/(1+√3)*(1-√3)/(1-√3)
BC=(6√6-6√18)/(1-3)
BC =(6√6 -18√2) /-2
BC=( 9√2-3√6cm
And for AB
AB / sin 45°=6/sin 75°
AB=6√3-1) cm
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