Ac=AD and AB bisects at angle A .show that Triangle ABC =triangle ABD .
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AC=AD (GIVEN)
Angle BAC=Angle Bad (AB is bisected at angle A)
AB=AB (common)
Triangle ABC = triangle ABD
Angle BAC=Angle Bad (AB is bisected at angle A)
AB=AB (common)
Triangle ABC = triangle ABD
Answered by
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Hey Mate ,
Here is the answer ,
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Given : AC = AD and ∠BAC = ∠BAD.
To prove : ΔABC ≡ ΔABD
Proof :
AC = AD {Given}
∠BAD = ∠BAC {Given}
AB = AB {Common}
ΔABC ≡ ΔABD {By SAS}
Hence proved.
______________________________________________________________
Hope this helped you !!
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Here is the answer ,
______________________________________________________________
Given : AC = AD and ∠BAC = ∠BAD.
To prove : ΔABC ≡ ΔABD
Proof :
AC = AD {Given}
∠BAD = ∠BAC {Given}
AB = AB {Common}
ΔABC ≡ ΔABD {By SAS}
Hence proved.
______________________________________________________________
Hope this helped you !!
Please mark as brainliest !!
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