AC= AE , AB= AD & angle BAD = angle EAC prove that BC = DE
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Solution:
In triangle ABC and ADE
AB=AD-------> Given
AC=AE------->Given
Angle BAD= Angle EAC-------> Given
=>Angle BAD+Angle DAC= Angle DAC+ Angle EAC
Adding Angle DAC to both sides
=>Angle BAC= Angle DAE
Therefore triangle ABC is congruent to triangle ADE-------> SAS Rule
Therefore BC=DE---------> C.P.C.T.
☺️✌️
In triangle ABC and ADE
AB=AD-------> Given
AC=AE------->Given
Angle BAD= Angle EAC-------> Given
=>Angle BAD+Angle DAC= Angle DAC+ Angle EAC
Adding Angle DAC to both sides
=>Angle BAC= Angle DAE
Therefore triangle ABC is congruent to triangle ADE-------> SAS Rule
Therefore BC=DE---------> C.P.C.T.
☺️✌️
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