Question

ac=de, acb=edf and bd=cf. prove that ab=ef.

Answer 1

Answer:

AB = EF

Step-by-step explanation:

In triangles ABC and DEF

1. AC = DE [Given]

2. Angle ACB = Angel EDF

BD = CF [Given]

CD = DC [Common]

=> BD + DC = DC + CF

3. BC = DF

Therefore, triangle ABC is congruent to triangle DEF [ SAS].

=>AB = EF [CPCT]

Answer 2

Given

AC = DE , ACB = EDF , BD = CF

To Find:

AB = EF

Explanation:

AC = DE

∠ACB = ∠EDF

BD = CF

In Δ ABC and ΔDEF

AC = DE

∠ACB = ∠EDF

BD + DC = CF + DC

BC = DF

By SAS congruency

Δ ABC ≅ ΔDEF

∴ AB = EF ( By C.P.C.T)

Hence proved AB = EF