ac=de, acb=edf and bd=cf. prove that ab=ef.
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Answered by
11
Answer:
AB = EF
Step-by-step explanation:
In triangles ABC and DEF
1. AC = DE [Given]
2. Angle ACB = Angel EDF
BD = CF [Given]
CD = DC [Common]
=> BD + DC = DC + CF
3. BC = DF
Therefore, triangle ABC is congruent to triangle DEF [ SAS].
=>AB = EF [CPCT]
Answered by
2
Given
AC = DE , ACB = EDF , BD = CF
To Find:
AB = EF
Explanation:
AC = DE
∠ACB = ∠EDF
BD = CF
In Δ ABC and ΔDEF
AC = DE
∠ACB = ∠EDF
BD + DC = CF + DC
BC = DF
By SAS congruency
Δ ABC ≅ ΔDEF
∴ AB = EF ( By C.P.C.T)
Hence proved AB = EF
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