AC is a chord of a circle with center O. The tangent at X to the circle meet extended diameter AB at D. Show that BD=BC,if∠D=∠A
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see the diagram. We use the principles that tangent and radius are perpendicular. The angle inscribed in a semicircle is 90 deg.
If angle D and A are equal then it comes that each of them is 90/3 = 30 deg.
In triangle BCD, the angles C and D are equal and hence, BD = BC.
If angle D and A are equal then it comes that each of them is 90/3 = 30 deg.
In triangle BCD, the angles C and D are equal and hence, BD = BC.
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