Question

Acan do a work in 6 hours while B and C alone can do the same work in thrice and twice the time respectively in how many hours can they finish the work working together

Answer 1

A = 6 (1)
total work = 6
b = 18
c = 12
total work = LCM of 6 ,12 ,18 = 36
efficiency =6, 3, 2
a+b +c = 36/11=

Answer 2

Answer:-

A can do a work in = 6hrs

B can do a work in = 3×6hrs= 18 hrs

C can do a work in = 2×6hrs=12 hrs

Total work = LCM of 6, 12, 18 = 36

= a+b+c

= 6+3+2

= 11hrs

= 36/11

= 3/3/11

HOPE IT HELPS YOU!!!!